LAWS OF EXPONENTS
By Patrica Hensley - Jefferson Davis Campus
LAW |
EXAMPLE |
1. xm xn = x m + n |
23 ·
25 = 28 = 256 |
2. x0 = 1 if x ¹ 0 |
20 = 1 |
3. x-n = 1/xn |
2-3 = 1/23 = 1/8 |
4. 1/x-n = xn |
1/2-3 = 23 = 8; 1/x-5 = x5 |
5. xm / xn = x m-n = 1/ x n-m |
212 / 28 = 24 = 16; x8 / x12 = 1/x4 |
6. xm / xm = 1 |
24 / 24 = 1 |
7. (xm)n = x mn |
(23)5 = 215 ; (x2)3 = x6 |
8. (xy)n = xn yn |
(2 · 4)3 = 23 · 43 = 8 · 64 |
9. (x/y)n = xn / yn |
(2/3)3 = 23/33; (1/3)5 = 1/ 35 = 3-5 |
10.(x/y)-n = (y/x)n |
(3/4)-2 = (4/3)2 = 16/9 |